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How do I find the roots and and coordinates of the vertex of the graph y = 2x^2 + 4x - 8 ?

y = 2x^2 + 4x - 8y = 2( x^2 + 2x - 4)Completing the square:y = 2( (x+1)^2 - 1 - 4 )y = 2(x+1)^2 -10the vertex of graph lies at the minimum value of y, and this occurs when x = -1:y = 2(-1+1)^2 -10y = -10t...

JA
Answered by Joe A. Maths tutor
7328 Views

Solve the equation 3^(5x-2)=4^(6-x), and show that the solution can be written in the form log10(a)/log10(b).

So we have the equation initially in the form 3^(5x-2)=4^(6-x), and as the solution involves log10, then  a sensible first move would be to take log10 of both sides, giving log10(3^(5x-2)) = log10(4^(6...

EB
Answered by Eloise B. Maths tutor
6126 Views

Prove that (sinx + cosx)^2 = 1 + 2sinxcosx

Starting on the left hand side we can expand out the brackets to get:
(sinx + cosx)(sinx + cosx)
sin2x+sinxcosx+sinxcosx+cos2x
Grouping together the like terms we can ...

AG
Answered by Adam G. Maths tutor
11223 Views

How do you integrate ln(x)?

Tricky. Definitely can't do it by inspection (we don't know any fuction that just differentaties to ln(x)), it's not like we've really got anything to substitute u for if we wanted to do it by substitu...

RG
Answered by Ross G. Maths tutor
94174 Views

Solve dy/dx= (x√(x^2+3))/e^2y given that y=0 when x=1, giving your answer in the form y = f(x)

The first thing we notice is that this differential equation is seperable, meaning we can get all of our y's on the left with a dy and all of our x's on the right with a dx. Doing this by multiplying b...

RG
Answered by Ross G. Maths tutor
12552 Views

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