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First simplify the expression; 3x^(2)-3 to get;
[(x+1)/3(x^(2)-1)] - [1/(3x+1)]
Using the fact that x^(2)-1 is the difference of two squares, we can simplify it to;
This is a standard parametric equations question, it is important that the methodology behind answering this question is understood.
For part a) we simply use the chain rule (dy/dx = dy/d...
We start with £800 in the bank. As we are earning compound interest, it means that each year we get 3.5% of the original £800, plus 3.5% of any interest that has already been earned...
Firstly, find the values of x where f'(x) = 0
f'(x) = 6x2 - 54
6x2 - 54 = 0
6(x+3)(x-3) = 0
x = 3, y = -108 and x = -3, y =...
(1)x2 4a - 10b = 22(2)x5 15a + 10b = 35(1) + (2) 19a = 57a = 3sub a = 3 into (1)2(3) - 5b = 116 - 5b = 11-5b = 55b = -5b = -1
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