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Using Pythagoras Theorem find the length of the hypotenuse of a right triangle where a=7 cm and b=11 cm. Round to the nearest tenth

Pythagos Theorem states that

a^2 + b^2 = c^2

So using the figures we are given the equation would look like this:

7^2 + 11^2 = c^2

We square the...

Answered by Mary B. • Maths tutor

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Using Trigonometric Identities prove that [(tan^2x)(cosecx)]/sinx=sec^2x

You should begin by identifying all the Trigonometric Identities that may be useful in this problem. Specifically, cosecx=1/sinx tanx=sinx/cosx 1/cosx=secx and possibly tan^2x + 1= sec^2x. I began by c...

Answered by Mary B. • Maths tutor

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A cylindrical beaker has a height of 16 cm and a diameter at its bottom of 10 cm. What is its volume? Give your answer to 2 decimal places.

As the beaker is a cylinder, we know the formula of its volume is (pi x (radius)²) x height.

Since the radius = 1/2 diameter and the diameter = 10 cm, the radius = 5 cm.

Answered by Aneesh S. • Maths tutor

23303 Views

Find the exact value of the gradient of the curve y=e^(2-x)ln(3x-2) at the point on the curve where x=2.

This is a typical gradient question for A2 papers, as it requires use of the Product Rule and Chain Rule, as well as knowledge of e^x.

Firstly, we can see that we will need to use the Pro...

Answered by Sophie K. • Maths tutor

10405 Views

Explain how to solve simulatentous equations.

A simultaneous equation is an equation with 2 unknowns( X and Y). You will have 2 seperate equations. By adding or subtracting the 2 equations, eliminate one of the unknowns(X0). You are now left with ...

Answered by Parth P. • Maths tutor

4098 Views