Search over 10,000 free study notes

First, we need to realise that we will be using the trigonometric identity sin(x)² + cos(x)² = 1
As our goal is to end up with an equation involving only sin, we will therefore ...

F'(x)=3x^2+4x-5
F(x)=(3/(2+1))(x^(2+1))+(4/(1+1)) (x^(1+1))-5(x^(0+1))

Answer: F(x)=x^3+2x^2-5x+c

P(WW) = 5/8 x 4/7 = 20/56

P(BB) = 3/8 x 2/7 = 6/56

P(same colour) = 20/56 + 6/56 = 26/56 = 13/28 (simplified)

AB = 4DB

AC = 2DB

Find BC using Pythagoras:

BC = √(4DB)² + (2DB)²

...

Step 1: 7k-21=3k-5

Step 2: 4k=16

Step 3: k=4