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First things first it will definately be useful to make a quick sketch of the x-y axes, the two points, and roughtly what the perpendicular bisector will look like.
This kind of question ...
Maths has always been a passion of mine from a young age. I've always enjoyed helping others with their maths as I find it extremely stimulating.
How you should approach a question of this type in an examSay you are given two lines: L1 and L2 with equations and you are asked to deduce whether or not they...
We label each equation
3x + 4y = 5 (1)
2x – 3y = 9 (2)
We now want to get rid of one of the variables (x or y). Lets get rid of x:
Here we will use:
cot(x) = cos(x)/sin(x)
cosec2(x) = 1 + cot2(x)
Chain rule : dy/dt * dt/ dx = dy/ dx
Product rule : d/dx (...
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