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For this question, we need to simplify the expression, and to do this, we first should rearrange the way it is written, so similar (or like) terms are next to each other. So in rearranging the expression ...

Quadratic equations are a slightly bit more tricky than other algebraic equations we might have seen before. They are called quadratic equations because one of the unknown values is squared (mutiplied by ...

Start by trying to find a common multiple of the last term, e.g. if you have a quadratic that ends in 4, when you factorise this function, we should get two terms ending in multiplies of 4 so (1,4) or (2,...

1) Multiply both equations so we have the same coefficient of one of the variables. This allows us to eliminate one of the variables and solve for the other. (4x + 5y = -8) --> Multiply b...

multiply both sides by 8 --> 4+x=16subtract 4 from both sides x=12