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We need the equation in the form (x+a)(x+b)=0. The numbers in the brackets (a and b) must multiply together to get the constant at the end of the equation, in this case 12. The numbers (a and b) must add ...

Let’s say we’re given the equation y=(2x-6)^4we would know how to differentiate x^4, therefore we can take the substitution u=2x-6 to give us the equation y=u^4we then differentiate this equation (dy/du) ...

Using the product rule H(X) = f(x)*g(x) and H'(X) = f'(x)*g(x) + f(x)*g'(x) Where, in this case f(x) = x³ and g(x) = e^x We can easily determine the derivative of the above function.f...

A quadratic equation will always take the form ax² + bx + c, where x is a variable and a, b and c are numbers. The equation may be given to you with several x² values, several x valu...

a) At A y=0, therefore if we solve: 0= (1/x)+1 we get x=-1.b)First step when drawing graphs is to find roots. x=0, x=2. Because x=0 acts as two of roots the graph only touches x=0. The graph is a positive...