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So we have to integrate these 3 terms one by one. To integrate 2x⁵ you add 1 to the power of x, so that becomes 6, you then divide the coefficient by the new power of x. So 3/6=1/2 giving the i...

The best way to solve simultaneous equations is by substitution. The first step is to pick a variable to eliminate. In this case, I'm going to choose to eliminate y because the first equation has a y on i...

Sin, cos and tan are functions that help you work out either, the missing angle or one of the missing lengths of a side in a right angle triangle.To work out the missing angle you need two side lengths, d...

b = (2a + 5)/3 Step 1 - Multiply both sides by 33b = 2a + 5Step 2 - subtract 53b - 5 = 2aStep 3 - divide by 2(3b - 5)/2 = a

differentiate both side with respect to x : (dy/dx)e^(-2x)+y(-2e^(-2x)) = 2+2y(dy/dx)
rearrange it : (-2y+e^(-2x))(dy/dy) = 2 + 2ye^(-2x) ==> dy/dx = ( 2 + 2ye^(-2x) ) / ( -2y+e^(-2x) )