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The width of a rectangle is X cm.  The length is 1·5 cm more than the width.  The perimeter of the rectangle is 17 cm. Write down an equation satisfied by X  and solve it to find X.

Let's call the length 'L', and the width 'X'. Since the length is 1.5cm more than width, we can form the equation: L = X + 1.5 (Equation 1)Let's call the perimeter 'P'....

Answered by Oliver D. • Maths tutor

7334 Views

Write the following in their simplest form: a) 8^0 b) 64^(2/3) c) 0.54545454...

a) 8⁰= 1b) 64^2/3 = (64^1/3)² = 4² =16c) 0.54545454... = x 100x = 54.545454.... 100x-x = 54 99x = 54 x = 54/99 x = 6/11...

Answered by Emmanuel S. • Maths tutor

3520 Views

You're on a game show and have a choice of three boxes, in one box is £10, 000 in the other two are nothing. You pick one box, the host then opens one of the other boxes showing it's empty, should you stick or switch?

At the moment of your first choice you have a 1/3 chance of picking the box with the prize and a 2/3 chance of getting nothing. After your choice those probabilities remain locked in and do not change as ...

Answered by Jonathan B. • Maths tutor

7977 Views

Solve the simultaneous equations: 5x+5y = 6 7x+3y = 6

Label the equations 1) 5x+5y = 6 and 2) 7x+3y = 6 . Then rearrange equation 1 to make x the subject of the equation: 5x = 6-5y. You would then simplify this equation to find the equation for x: x = 6/5 - ...

Answered by Isobel B. • Maths tutor

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