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Can you solve (2x-4)(x+1)=0?

All we need to do here is find the values of x that make each bracket zero.So2x-4=02x=4x=2andx+1=0x=-1

SI
Answered by Samuel I. Maths tutor
5965 Views

Form the differential equation representing the family of curves x = my , where, m is arbitrary constant.

Differentiating the above equation with respet to y:dx/dy = m;Substituting the value of m in the given form:x = (dx/dy) y i.e. the solution is(dx/dy) y - x = 0

PS
Answered by Piyush S. Maths tutor
8224 Views

In triangle ABC, right angled at B, AB = 3 cm and AC = 6 cm. Determine angle BAC and angle ACB.

Using the trignometric principles,sin (ACB) = AB/AC = 3/6 = 1/2Thus, angle ACB = 30 degreesand angle BAC = 90 - angle ACB = 60 degrees

PS
Answered by Piyush S. Maths tutor
16157 Views

Find the zeroes of the quadratic polynomial x^2 + 8x + 15.

x2+8x+15 = (x+3)(x+5)So, the value of x2+8x+15 is zero when x2+8x+15 = 0 i.e. x = -3 or x = -5.

PS
Answered by Piyush S. Maths tutor
22113 Views

factorise x^2+10x+21

firstly the largest power is x^2 so when factorising we know that both brackets must involve an x plus or minus a number.

next we look at the 21 and we need two numbers that multiply toge...

RC
Answered by Ross C. Maths tutor
21203 Views

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