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the aim of finsing the inverse is making x the subject. To start we need to multiply both sides by: (x-1), giving us:y(x-1) = 2x+1now we need to expand the brackets:yx - y = 2x+1now gather all the x compo...
To find the inverse we're wanting to make x the subject. First start by multiplying both sides by (x-1), this gives us y(x-1) = 2x+1. Expand the brackets giving yx - y = 2x+1. Gather all the x components ...
Y=(2x-3)/x2
Quotient Rule: dY/dx(u/v)=(u'v-v'u)/v2
dY/dx=(2x2-2x(2x-3))/x4
=(6x-2x2)/x4 (C...
First write cosh and sinh as exponentials, from their respective definitions:sinh x = 1/2 (ex - e-x)cosh x = 1/2 (ex + e-x)So: 3 * 1/2 (ex + eWUAnswered by William U. • Maths tutor21486 Views
In order to calculate the derivative of the given function, we need to apply the laws of derivation. Therefore:f '(x) = ((x+2)/(x-1))'f '(x) = [(x+2)' * (x-1) - (x+2) * (x-1)' ]/ (x-1)2CBAnswered by Cosmin B. • Maths tutor5173 Views
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