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Solve the following simultaneous equations to find x and y.

2x2 - 2y = 282y - 4 = 12x
y - 2 = 6xy = 6x + 2
Substitute y = 6x + 2
2x2 - 2(6x + 2) = 282x2 - 12x - 4 = 282(x2 - 6x - 2) = 28x2 - 6x ...

PD
Answered by Prahlad D. Maths tutor
2804 Views

Find two positive numbers whose sum is 100 and whose product is a maximum.

Call the two numbers x and y. The constraint is that x + y =100, and we need to maximise A=xy.
Rearrange the constraint to y = 100 - x, and substitute into the product equation.
A = x(100-x) = ...

Answered by Maths tutor
22784 Views

Solve the integral: int(x^3+4x^2+sinx)dx.

First, since there are terms with different factors of x summing together, we can separate these into three individual integrals as follows:int(x3 dx) + 4int(x2dx) + int(sinx dx)Then...

Answered by Maths tutor
3239 Views

A triangle has sides of 4cm and 5cm with the hypotenuse unknown. What is the length of the unknown side?

Pythagorus' theorem a^2 + b^2 = c^2
4^2 + 5^2 = c^216+25 = c^241 = c^2Root 41 or 6.403 = c

Answered by Maths tutor
2964 Views

A curve C has equation: y = x^2 − 2x − 24x^1/2, x > 0; Find (i) dy/dx (ii) d^2y/dx^2

i) let dy/dx = ans, where ans = y, where you multiply the coefficients of each constant of x by the power and reduce the power by 1 in the equation ytherefore dy/dx = 2x - 2 - 12x-1/2ii) repeat...

CH
Answered by Charles H. Maths tutor
4374 Views

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