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2x2 - 2y = 282y - 4 = 12xy - 2 = 6xy = 6x + 2Substitute y = 6x + 22x2 - 2(6x + 2) = 282x2 - 12x - 4 = 282(x2 - 6x - 2) = 28x2 - 6x ...
Call the two numbers x and y. The constraint is that x + y =100, and we need to maximise A=xy.Rearrange the constraint to y = 100 - x, and substitute into the product equation. A = x(100-x) = ...
First, since there are terms with different factors of x summing together, we can separate these into three individual integrals as follows:int(x3 dx) + 4int(x2dx) + int(sinx dx)Then...
Pythagorus' theorem a^2 + b^2 = c^24^2 + 5^2 = c^216+25 = c^241 = c^2Root 41 or 6.403 = c
i) let dy/dx = ans, where ans = y, where you multiply the coefficients of each constant of x by the power and reduce the power by 1 in the equation ytherefore dy/dx = 2x - 2 - 12x-1/2ii) repeat...
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