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Prove that the square of an odd number is always one more than a multiple of 4

If we say n is any number, then we know 2n represents an even number - any number multiplied by 2 is always even. 2n+1 represents an odd...

Answered by Rebecca R. • Maths tutor

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Simply fully (3x^2 - 8x - 3) / 2x^2 - 6x
(3x² - 8x - 3) / 2x² - 6x == (3x + 1)(x - 3) / 2x² - 6x == (3x + 1)(x - 3) / 2x(x-3) == 3x+1 / 2x

GR
Answered by Gabriel R. • Maths tutor
3117 Views

Solve (5− x)/2 = 2x – 7
(5-x)/2=2x-7 5-x=4x-14 5=5x-14 19=5x x=19/5

AP
Answered by Abigail P. • Maths tutor
8327 Views

Show that x^2 - 8x +17 <0 for all real values of x
consider the discriminant b²-4ac 8²-4x1x17 64-68=-4 discriminant is below 0, there are no real roots therefore x² - 8x +17 <0

Answered by • Maths tutor
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Calculate the first derivative of f( x)= 3x^3+2x^2-5
f’(x)= 9x^3+4x

Answered by • Maths tutor
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Prove that the square of an odd number is always one more than a multiple of 4

Simply fully (3x^2 - 8x - 3) / 2x^2 - 6x

Solve (5− x)/2 = 2x – 7

Show that x^2 - 8x +17 <0 for all real values of x

Calculate the first derivative of f( x)= 3x^3+2x^2-5

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