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x (x-4) = 32X^2-4x-32 = 0(x-8)(x+4) = 0 x=8perimeter =8+4+4+8 = 24cm.

y = arctan(x)tan(y) = xsec²(y) = dx/dyfrom cos²A + sin²A = 1, we know that 1 + tan²A = sec²A (divide by cos²A), so we substitute in1 + tan...

To begin this question, it is first necessary to separate the different parts: the numbers, the as and the bs.The number division is simple. 24/6 = 46b has no values of a. Therefore, the a remains untouch...

This indefinite integral (has no defined limits) should be evaluated by integration by substitution This is because you cannot integrate sin²xWhen doing integration by substitu...

This can be done with integration by substitution. If we let u=tanx then du/dx=sec^2(X). If we substitute U into the integrand we get it being u(sec^2(X))dx. rearranging the du/dx equation to make dx the ...