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Solve these simultaneous equations 2y+x=8, 1+y=2x.

When solving simultaneous equations the first step is to take one of the equations and rearrange it to make one of the terms the subject. In this case lets take the equation 1+y=2x. Take the 1 over to the...

Answered by Lewis K. • Maths tutor

3446 Views

Find the value of roots of the quadratic: x^2-13x=30

First rearrange the equation so the LHS is equal to Zero:X²-13x-30=0Then find the factors of -30:-1,30/1,-30-2,15/2,-15-3,10/3,-10-6,5/6,-5Chose the factor pairs which add to equal -13which is ...

Answered by Tabonga Z. • Maths tutor

2935 Views

Solve ((6+x)/2) + ((2-3x)/3) = 31/6

To solve this first we need to simplify the equation by multiplying the denominators by a common factor. If we multiply both sides of the equation by 6 we shall get an equation that is expressed with deno...

Answered by Ellis J. • Maths tutor

3503 Views

A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

Using the chain rule, we know that dy/dx = dy/dt . dt/dx Therefore we differentiate both equations with respect to t:dx/dt = -4dy/dt = -2/(t^2)therefore dy/dx = -1/4 . -2/(t^2)dy/dx = 1/(2t^2) ... (we kno...

Answered by Brandon A. • Maths tutor

3135 Views

There are 10 boys and 20 girls in a class. The class has a test. The mean mark for all the class is 60 The mean mark for the girls is 54 Work out the mean mark for the boys.

The mean of the class is 60 for 30 students in total so to get the total marks scored by the class you need to multiply 60 by 30 which is 1800. Then you need to work out the total marks scored by the girl...

Answered by Thomas B. • Maths tutor

2808 Views