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Solve the simultaneous equations: 5x + y = 21 and x - 3y = 9

x = 4.5y = -1.5To answer this question, first, rearrange the first equation to make y the subject: 5x + y = 21 --> y = 21 - 5xYou can now substitute this value of y into the second equation: x - 3(21 -...

SA
Answered by Sophie A. Maths tutor
3808 Views

How do you solve integrals which are the result of a chain rule e.g. the integral of sin(2x+1)

∫sin(2x + 1)dx[newline]In this case the easiest way to solve the integral is to perform a substitution. The substitution should reduce the integral to something you can solve. In this case we will[newline...

SN
Answered by Sean N. Maths tutor
1329 Views

Factorise 100-x^2

Via inspection, one can factorise this via the difference of squares; since a^2-b^2 = (a+b)(a-b), therefore:100-x^2 = (10-x)(10+x)

HM
Answered by Howard M. Maths tutor
6947 Views

Via the product rule, or otherwise, differentiate 'y = xsin(x)'.

SInce, for y = uv, dy/dx = uv' + vu', where u' = du/dx, therefore:dy/dx = (1sin(x)) + (xcos(x)) = sin(x) + xcos(x)

HM
Answered by Howard M. Maths tutor
3234 Views

Solve the simultaneous equations: 3y + 2x = 10, 4x - y + 3 = 2

The first step whenever you are given an equation is to group like terms. By this I mean put all the terms with the same letter next to it together and, in this case, the numbers without a letter. For the...

TM
Answered by Tom M. Maths tutor
3730 Views

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