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In the triangle ABC, AB = 16 cm, AC = 13 cm, angle ABC = 50 and angle BCA= x Find the two possible values for x, giving your answers to one decimal place.

Using the sine rule: sina/A = sinb/Bsinx/16 = sin50/13sinx = 16 * (sin50/13)sinx = 0.943x = 70.5 and 109.5

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Find the general solution of the differential equation: d^2x/dt^2 + 5dx/dt + 6x = 2cos(t) - sin(t)

First solve complementary function, i.e. d²x/dt² + 5dx/dt + 6x = 0. To do so, let x = e^mt, where m = arbitrary constant. Differentiating gives dx/dt = m e^mt and...

Answered by Mick G. • Maths tutor

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Using the product rule, differentiate: y = (x^2 - 1)(x^3 + 3).

y=(x²-1)(x³+3) ...

Answered by • Maths tutor

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integral of (tan(x))dx using the substitution u = cos(x)

given u = cos(x), therefore du/dx=-sin(x), as tan(x)=sin(x)/cos(x), can rewrite tan(x)=(-du/dx)/u, therefore integral can become [(-1/u)du], after inegrating you are left with -ln(u)+c, therefore ln(1/u)+...

Answered by Frederick R. • Maths tutor

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f(x) = x^x, find f'(3).

Therefore, y = x^xcan then natural log both sides leaving ln(y) = xln(x) then differentiating both sides wrst to x d/dx(ln(y)=xln(x))we are then left with this expression (dy/dx)(1/y)=ln(x)+1 mu...

Answered by Frederick R. • Maths tutor

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