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Simplyfy, ((x-2)(x^2+5x+6)-(2x^2+10x+12))/(x^2+x-2)

The key to this is to not expand everything out and try work it out through that process. The easiest way is to notice that (x^2+5x+6) = (x+2), (2x^2+10x+12)=2(x+3)(x+2) and (x^2+x-2)= (x+2)(x-1).From thi...

TL
Answered by Thomas L. Maths tutor
3194 Views

Express 280 as a product of its prime factors.

2 * 2 * 2 * 5 * 7 = 280

DS
Answered by Danny S. Maths tutor
6348 Views

Solve the simultaneous equations y = 5x^2 + 4x - 19 and y = 4x + 1

Okay, so for two simultaneous equations which both equal the same variable (in this example the variable they're equal to is y), the trick is to make both equations equal each other:so we can say that 4x ...

GH
Answered by Guy H. Maths tutor
10771 Views

Solve x^2 - x - 12

As it is a quadratic, I can use the quadratic equation, or (-b +/- sqrt(b2-4ac))/2aHere our a = 1, b = -1 and c = -12. Substitute into the quadratic equation, this becomes (1 +/- sqrt(1 + (4*12...

FW
Answered by Freya W. Maths tutor
3930 Views

Find both roots of the following equation x^2 + 2x - 4 = 0

There are many methods available to solve this - let's use the quadratic formula in this case.We know the formula is x = (-b +- sqrt(b^2-4ac))/2a.Here a=1,b=2,c=4,Hence, we know that x = (-2 +- sqrt(4 - -...

AH
Answered by Amir H. Maths tutor
3364 Views

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