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15a2+ab-6b2 =(?a+?b)(?a-?b) Factors of 15= 3 and 5 Factors of 6= 2 and 3 If we try (3a+2b)(5a-3b) that gives us 15a2+10ab-9ab-6b2 = 15a2+ab-6b2 therefore the answer is (3a+2b)(5a-3b)

(i) S₄=2+4+6+8=20

(ii)S₁₀₀= 2+4+...+200=2(1+2+...+100)=2(100+1)*(100/2)=10100

x^5+C

5(x+4)-3(2+3x)

Expand first bracket 

5x+20-3(2+3x) 

Expand second bracket

5x+20-6-9x

simplify

14-4x

Using the product rule: d/dx(ab)=ab’ + a’b where a and b are variables which have been differentiated with respect to x

Derivative: 2(x^2(dy/dx)+2xy) + 2 + 4dy/dx+πsin(πy)...