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to find the first part we just need to plug in the value-7 in the expression for f replacing our independant value, x .f(-7)=(2*(-7)-7)/4 =(-14-7)/4 =-21/4to find the second part we need to interchange th...
Parallel lines have the same gradient. The gradient of L1 is 4. For the gradient of L2: 3y=12x-4y=4x-4/3The gradient of L2 is also 4. Thus these lines are parallel. Explanation 1.Rearrange th...
Firstly we would approach the question by looking at the question by attempting to group together the x terms to solve for x. By looking at the question we can see that the x terms are the denominators so...
Firstly we need to realise that equation 1 (x^2 + y^2 = 9) does not factorise. So once realising this, we must rearrange equation 2 (x + y = 2) so that y = 2 - x. Now we substitute (y = 2 - x) into equati...
(x-5) (x-2)
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