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This would be a question that would test the students understanding of Pythagoras' Theorem. When teaching this before I have often found that students are scared of thee questions because of the name, so ...

First find the difference between the numbers. Do this by subtracting the first number from the second number...

18

-7

11

Double check this to see if this runs true for ...

a) y = 9 -6x^2 - 12x^4 

dy/dx = -12x - 48x^3 

b) At stationary points dy/dx = 0. 

-12x - 48x^3 = 0 

48x^3 + 12x = 0 

4x^3 + x = 0

x (4x^2 + 1) = 0 

Either ...

1. We the answer in question in the form A(1+B)^0.5 and we can do that by factorising out the 5. This gives 5^0.5(1+0.4x)^0.5. 2. Identify the formula we are going to use ...

The formula you are given is an equation which is written in terms of x. So we will be differentiating with respect to x. 

When differentiating we take the current power and place that in front of ...