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Line L1 passes through points (4,6) and (12,2). Line L2 passes through the origin and has gradient -3. The two lines intersect at point P. Find the co-ordinates of P.

Gradient of L1 : Gradient = Change in y/ Change in x. Gradient = (2-6)/(12-4)= -1/2
Gradient is "m" in y=mx+cPlug in a point to determine c : 6 = -1/2 *4 + c --> c =8 L1 is ...

Answered by Bjorn L. • Maths tutor

6590 Views

Using the quadratic formula find the solutions for x^2+x-6

By subbing in a=1 b=1 and c=-6 into the quadratic formula, you should get two solutions of x which are x = 2 and x = -3

Answered by Loretta O. • Maths tutor

2924 Views

Write x^2 + 4x - 16 in the form (x+a)^2-b

Concentrate on the x^2+4x. Halve the 4 or any number that occupies that space. Equals 2 in this case. Put (x+2)^2 and that is your first term. Expand the brackets= x^2 + 4x + 4. Don't want the extra + 4 a...

Answered by Lucy B. • Maths tutor

9867 Views

a=7 and b=2, Work out the value of (a/b)-a^b

(7/2) - 7²(7/2) - (98/2)= -(91/2)

Answered by Lauren P. • Maths tutor

8624 Views

A curve has the equation y=3x^3 - 7x^2+52. Find the area under the curve between x=2 and the y-axis.

With a question like this. Firstly you have to read it, of course. But more importantly you have to understand what it is asking of you. So it is asking to find the area with boundaries at x=2 and the y a...

Answered by Calvin C. • Maths tutor

3597 Views