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Line segment AB is drawn between point A(-3, 3) and point B(-1, -1). Work out the gradient of the line segment AB, then find the equation of the graph.

The gradient of segment AB is given by the change in x, over the change in y.m = dy/dx = (y2 -y1)/(x2-x1)y2 = 1y1 = 3x2 = -1x1 = -3m = (-1 - 3)/(-1 -(-3)) = -4/2 = -2Gradient is -2.

SA
Answered by Shahan A. Maths tutor
7005 Views

How do you find the length of the diagonal of a rectangle of 5cm by 12cm?

Draw the rectangle and put on the measurements Draw on the diagonal Find the right angled triangle Pythagoras tells us a2+b2=c2 where c is the longest side which is what w...

MS
Answered by Matthew S. Maths tutor
2859 Views

For the curve y = 2x^2+4x+5, find the co-ordinates of the stationary point and determine whether it is a minimum or maximum point.

Stationary points occurs when the gradient of the graph is equal to 0, i.e. dy/dx = 0. Differentiate y with respect to x to get dy/dx = 4x + 4.So making 4x + 4 = 0 gives x = -1. Substituting this into the...

OB
Answered by Owen B. Maths tutor
4853 Views

Find the x co-ordinate of stationary point of the graph y=5x^3 +3x

When you differentiate the function that gives the gradient. Therefore differentiate to get dy/dx= 15x^2 + 3. Make this equal to 0 to get 15x^2 + 3=0 and rearrange to get the value of x as required so 15x...

VJ
Answered by Vinay J. Maths tutor
3246 Views

Factorise 5a – 3a^2

Answer: a(5-3a)Explanation: We take the highest common factor of both of the terms, which is a and we put it outside of the bracket. Then, in the bracket we put two terms that when multiplied by a, the pr...

CM
Answered by Christina M. Maths tutor
9541 Views

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