Top answers

Maths
All levels

Differentiate y = x^2 - 2x-3 + e^3x + 2ln(x)

The above function has several components with different rules on how to differentiate each of them. For each:(1) y = x2dy/dx = 2x This follows the general rule of differentiating polynomials: ...

JH
Answered by Jim H. Maths tutor
3394 Views

A curve is defined by the parametric equations x = 2t and y = 4t^2 + t. Find the gradient of the curve when t = 4

the gradient of the curve = dy/dx
and dy/dx = (dy/dt)(dt/dx)
dy/dt = 8t + 1
dx/dt = 2 therefore dt/dx = 1/2
dy/dx as above = (8t + 1) * 1/2 = (8t + 1)/2
where t = 4, dy/dx = (8*4...

AB
Answered by Angus B. Maths tutor
5081 Views

Nancy is driving and makes a wrong turn. The satnav indicates that her journey will take an extra 7 minutes. Nancy drives at an average speed of 60km/h to the nearest 5km/h. What's the greatest possible distance traveled in this detour in km to 2.d.p?

Start by selecting useful information in the text.time = 7 minutesspeed = 60km/h to the nearest 5km/hmaximum possible distance travelled = ? kmWe know a time and speed and want to know a distance. So we c...

LG
Answered by Louis G. Maths tutor
2550 Views

Solve 7x+6>1+2x

For this such question, we need to find what values x can be. We need to get all the terms containing x one side of the equation and all the other terms on the other side then isolate x. To do this, we mu...

AM
Answered by Annie M. Maths tutor
5258 Views

a) i) find dy/dx of y = 3x^4 - 8x^3 - 3 ii) then find d^2y/dx^2 b) verify that x=2 at a stationary point on the curve c c) is this point a minima or a maxima

So the first step is to find the first differential of yTo do this we simply have to differentiate:so with C being our coefficient, n being the power that x is.we need to reduce the power of x by 1, whils...

CM
Answered by Charlie M. Maths tutor
3083 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences