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How to find the longest side of a right-angled triangle if we are given the two other sides?

We can find the longest side of a right angled triangle (also called the hypotenuse) by using Pythagoras' Theorem and considering the lengths of the two other sides given to us. Pythagoras' Theorem is wri...

Answered by Denzel C. • Maths tutor

18618 Views

Differentiate the following: y=sin(x^2+2)

dy/dx = 2xcos(x²+2)

Answered by Matthew B. • Maths tutor

3595 Views

make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

Answered by Sofia A. • Maths tutor

4946 Views

Write down the length of side "a"

Using Pythagoras' theorem: a² = b² + c²You can use the length of the other two sides to calculate a.

Answered by Rhys K. • Maths tutor

2921 Views

Solve these simultaneous equations 2y+x=8, 1+y=2x.

When solving simultaneous equations the first step is to take one of the equations and rearrange it to make one of the terms the subject. In this case lets take the equation 1+y=2x. Take the 1 over to the...

Answered by Lewis K. • Maths tutor

3697 Views