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Let's start by recalling that two lines are parallel when their gradients are equal. We know that the gradient of the line y=mx+c, is m. So the gradient of L1 is 5 as the equation of the line is already i...

This answer has 3 steps:1) find the derivative, f’(x), of the function2) factorise the derivative 3) set equal to zero and solve for x1) f’(x) = 3x^2 + 6x - 242)f’(x) = 3(x^2 + 2x - 8)3) x^2 + 2x - 8 = 0 ...

Firstly draw a diagram of the problem.Then resolve the forces into their components parallel and perpendicular to the plane.Resolving parallel: P + Fmax = 3gsin(60) equation 1.Resolving perpendicular: R =...

QUESTION (a) R = U(n+1)/U(n ) = 5/25= 0.2(b) (i) U(10) = 25 x (1/5)^9 = 0.0000128 (ii) U(n) = 25 x (1/5)^(n-1)(c) S = U(1)/(1-r) = 25/(1-(1/5))=25/(4/5))=125/4=31.25

In order to solve this problem we will have to use the product rule as follows: d/dx[x^3⋅cos(5⋅x)]=[d/dx(x^3)]⋅cos(5x)+(x^3)⋅[d/dx[cos(5x)]]=(3⋅x^2)⋅cos(5⋅x)+(x^3)⋅−5⋅sin(5⋅x)=3⋅x^2⋅cos(5⋅x)−5⋅x...