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An area of a garden needs to be tiled. It consists of a square area of 10m by 10m, with an outdoor pool in the middle of radius 3m. The tiles to be used are 50cm by 50cm, and cost 50p per tile. Find out how much it will cost to tile the area.

Calculate total area of space: A = 1010 = 100m2Calculate area of pool: A = Pir2 = 3.14232 = 28.27m2Difference in area = 100m2

MC
Answered by Matthew C. Maths tutor
3121 Views

solve the equation x^2 -5x +1 = 25

We can see from the term x^2 that this equation is quadratic. To solve it, we need to get it into the form ax^2 +bx +c = 0. Subtract 25 from both sides to reach this form:So we have the equation x^2 -5x -...

FS
Answered by Frederick S. Maths tutor
3052 Views

By first expanding the brackets, differentiate the equation: y=(4x^4 + 3x)(2x^2 - 9)

In this case the question has given you a clue as to the order that you solve the question. So, first we need to expand the brackets, multiplying each term by one another to get; y=8x^6 - 36x^4 + 6x^3 - 2...

PA
Answered by Patrick A. Maths tutor
3636 Views

Work out the equation of the normal to the curve y = x^3 + 2x^2 - 5 at the point where x = -2. [5 marks]

Firstly, we need to differentiate the function of the curve y = x^3 + 2x^2 - 5. Using d/dx (x^n) = nx^(n - 1), we get dy/dx = 3x^2 + 4x. To find the gradient of this curve, we then need to evaluate dy/dx ...

AG
Answered by Amy G. Maths tutor
4239 Views

Let f(x) = x^2 - 1. A vertical translation of 3 and a horizontal translation of -2 is applied. Write the new function g(x) in the form g(x) = ax^2 + bx + c

Let f(x) = x2- 1To apply a vertical translation, simply add the value to the overall equation. In this case it is p...

JH
Answered by Jack H. Maths tutor
2745 Views

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