Top answers

Maths
All levels

The point A lies on the curve with equation y=x^0.5. The tangent to this curve at A is parallel to the line 3y-2x=1 . Find an equation of this tangent at A. [5 marks]

Differentiate equation

dy/dx=0.5*x-0.5

Gradient is the same as the second equation

2/3=0..5*x-0.5 

Solving this ...

AM
Answered by Arnold M. Maths tutor
6340 Views

Find the points that the graph "y = x^2 -4x -14" touches the x-axis

(2+3√2, 0)  and (2-3√2, 0)

TC
Answered by Thomas C. Maths tutor
3298 Views

Differentiate (4x+9)^3

(3*4)(4x+9)^(3-1)

Where 4 is the derivative of inside the brackets and 3 is the power of the brackets.

Therefore the answer is 12(4x+9)^2

AT
Answered by Alexander T. Maths tutor
4917 Views

If z1 = 3+2i, z2= 4-i, z3=1+i, find and simplify the following: a) z1 + z2, b) z2 x z3, c)z2* (complex conugate of z2), d) z2/z3.

(a) For part a, simply add the real terms together and the imaginary terms together. z1+z= (3+2i)+(4-i) = 7+i b).     

(b) For part b, multiply the brackets out, remembering...

JS
Answered by Jaspa S. Maths tutor
13566 Views

how can differentiate using the product and chain rule? e.g y=(4x+1)^3(sin2x), find dy/dx.

First you have to identify the equation for y is a product. Then you can apply the product rule using (4x+1)^3 as one term and sin2x as the other. First you differentiate (4x+1)^3 using the chain rule. Yo...

RJ
Answered by Rajvir J. Maths tutor
4594 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning