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Gradient of initial line = 3/4 Equation of initial line : y= 3/4x + 5/4 (4y = 3x + 5) Equation of perpendicular line : y= -4/3x
a.) simplify and expand (x+3)(2x+5) Expand using "crab claw" (better known as foil) => 2x^2 + 5x + 6x + 15 Simplify => 2x^2 +11x + 15 b.) differentiate (x+3)(2x+5) Using part a, dy/dx= 4x...
Firstly you need to identify the information in the question that is key. On analysing the question, you will see that the objective is to find what x is and what y is respectively. We are given two separ...
There are several ways one can go about answering this question, one of which is to 'complete the square' by trial and error. A different, potentially easier method is to substitute the coefficients into ...
For M1, it is essential for you to be able to solve questions that involve particles moving in a straight line with constant acceleration.
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