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Quadratic inequalities generally don't arrive in the standard quadratic form (Ax^2 + Bx +c) and so can be sometimes difficult to spot. However, if you see an X^2 - or brackets that expand to X^2 - on eith...
Factorise the quadratic into two brackets to make (x-3)(x-5)=0 Because the product of these brackets is zero then the value of one of the brackets must equal zero. In order for one of the brackets to have...
Use the FOIL method to remember which components you need to multiply together. F= First two, O= ONSAnswered by Natasha S. • Maths tutor54419 Views
We'll need to use the product rule.
Let's take u = x^2 -> du/dx = 2x, and v = ln(x) -> dv/dx = 1/x
Then dy/dx = x^2(1/x) + 2xln(x) = x + 2xln(x)
Substituting our x value gives (...
5w -3 = 3w + 15
Need to get the numbers on one side, and letters on the other side.
5w = 3w + 15 + 3
5w - 3w = 15 + 3
2w = 18
w = 18/2
w = 9
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