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The two terms in the quadratic equation share the factors 2 and x, so these can be brought outside the bracket as shown: y = 2x(3x-2). In order to solve ...

X^2 + 4X - 12X^2 + yX + z(x + a)^2 + ba = y/2a = 4/2 = 2b = z - a^2b = -12 -2^2 = -16Therefore: x^2 + 4x - 12 = (x+2)^2 - 16

Treat each component separately and break it down...Note that when a number has a power that is a fraction, the numerator acts as a power and the denominator acts as a root(16)^1/4 = 2. Okay, brilliant!So...

The aim of this question is to algebraically manipulate the equation to end up with an equation with s on its own, on one side, making it the subject of the equation.We will start by looking at the terms ...

Let x = 0.2565656...Then 10x = 2.565656.... and 1000x = 256.565656...So 1000x - 10x = 256.565656... - 2.565656... = 254990x = 254 x = 254/990 = 127/495