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What actually are sin, cos and tan?

This is a common question asked by my students when they first learn about trigonometry. First draw a unit circle on the plane and the graphs of sine and cosine next to it. The circle obviously has 360 de...

LP
Answered by Leon P. Maths tutor
5040 Views

The point P (4, –1) lies on the curve C with equation y = f( x ), x > 0, and f '(x) =x/2 - 6/√x + 3. Find the equation of the tangent to C at the point P , giving your answer in the form y = mx + c. Find f(x)

First step is to understand all the notation, i.e. the prime for derivative. We then need to understand that the derivative is the gradient of the tangent at a point. In this case at the point P we can fi...

LP
Answered by Leon P. Maths tutor
15373 Views

Let g (x) = 2x sin x . (a) Find g′(x) . (b) Find the gradient of the graph of g at x = π .

a)   f'(x)=uv'+vu'     if    f(x)= uv

u=2x  u'=2  v=sin(x)   v'=cos(x)

g'(x)=2x cos(x) +2sin(x)

b)   g'(π) = 2π cos(π)+2sin(π)  = 2 π (-1) + 2 (0)

      g'(π) = -2π

MB
Answered by Matias B. Maths tutor
10381 Views

Differentiate sin(x)cos(x) using the product rule.

The product rule states (assuming x' is the differential of x): (fg)​′​​=f​′​​g+fg​′​​ Substitute the values into the rule: (sin(x)cos(x))' = sin(x)'cos(x) + sin(x)cos(x)' (sin(x)cos(x))'...

MP
9663 Views

For the equation y=2x+7, what is the gradient and the y intercept?

For all straight line equations as the one above, the equation is y=mx+c where: m is the gradient, c is the y-intercept. Thus from the arrangement of the given equation, gradient ...

MP
19703 Views

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