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This question can be solved in two ways. One way is to divide the whole equation, both sides by 3, which gives x-2=7. Then add 2 to both sides to give x=9. Another way is to work out the left hand side of...

This is a simple quadratic equation. To answer the question, it must first be factorised before it can be solved. To do this, two numbers need to be found which multiply to make the constant term and have...

x=4t-7 take the -7 over first, swapping the sign as it passes over the equals sign x+7=4t 4t = 4*t so we need to divide the other side of the equation by 4 1/4(x+7)=t

Factorise: X^2 means 2 brackets (x )(x )=0 factors of 1 = 1 (x 1)(x 1)=0 to get minus 2 you must do (-1) + (-1) so (x-1)(x-1)=0 therefore x-1=0 and x=1

Re-arrange (1) : y = 2x + 4 Square both sides: y^2 = 4x^2 + 16 Substitute (1) into (2) and simplify: 2x^2 + 9x + 4 = 0 Factorise the equation: (2x+1)(x+4) = 0 Solve for x: x = -1/2 and x = -4 Substitute t...