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There are two ways to solve this equation. In the first method, we can simplify the quadratic by observation into two linear equations multiplied together, giving us (2x + 1)(x + 1) = 0. We can then set e...

By the quadratic formula, where a = 3, b = 5, c = 2 x = -2/3 and x = -1

(7,0)

One helpful method for solving questions like these is to sketch the curve in stages. First begin with the straight line y=3x+4 (taking 3x+4 from within the modulus lines) crossing the x axis at -4/3 and ...

sin(A+B) ≡ sin(A)cos(B) + sin(B)cos(A)

⇒ sin(75°) = sin(30+45)° = sin(30°)cos(45°) + sin(45°)cos(30°)

= ½ × 1/√2 + 1/√2 ×(√3)/2 = 1/(2√2) + (√3)/(2√2)

= (1+√3)/(2√2)