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First of all, you need to read the question really carefully and look at how many marks it is worth. The question is worth two marks and it is asking you to do two things: firstly, you need to ‘rationalis...

4x+5=6x-13. Take 4x from both sides 5= 6x-4x-13 5=2x-13. On the right hand side, you have -13 value. Add 13, to make 0. Adding thirteen on right also adds thirteen on left. 5 + 13 = 2x - 13 + 13 18=2x. 2 ...

tanx = sinx/cosx. Express this as: sinx*(cosx)^-1. Remembering the product rule: "y = f(x)g(x), dy/dx = f'(x)g(x) + f(x)g'(x)". sinx differentiates to cosx and cosx differentiates to -sinx. Also...

This is a handy trick for quadratic equations ax^2 + bx + c = 0.

e.g. (x^2 + 5x + 6). So a = 1, b = 5 and c = 6.

To complete the square, let x^2 + 5x + 6 = 0. Then, take 6 to the other side ...

In order to complete this question we need to use the quotient rule (i.e. if an equation is of the form h(x)=f(x)/g(x) then h'(x)=(g(x)f'(x)-g'(x)f(x))/g(x)^2).In our example f'(x)=cos(x),g'(x)=15...