Top answers

Maths
All levels

Solve the simultaneous equations: y=5-x and y=x+1.

Since y is equal to both 5-x and to x+1, we know that 5-x is equal to x+1. We can write 5-x=x+1. Take 1 away from each side: 4-x=x. Then add x to each side: 4=2x. Divide both sides by 2: 2=x. Now we have ...

CW
Answered by Charlotte W. Maths tutor
19256 Views

Work out 51% of 400? (No calculator)

Finding 51% of 400 is the same as finding 50% of 400, and 1% of 400, and adding them together. Finding 50% of a number is the same as finding half of the number, since half of 100% is 50%. Half of 400 is ...

CW
Answered by Charlotte W. Maths tutor
25908 Views

Differentiate y = √(1 + 3x²) with respect to x

To solve this question, we need to use the chain rule, because the function is too complicated to solve simply by inspection. The chain rule says that dy/dx = dy/du × du/dx, where u is a function of x. In...

WT
Answered by Walter T. Maths tutor
8751 Views

Given h(x) = 9^x + 9 and g(x) = 10*3^x, find {x | h(x) < g(x)}.

This question is asking to find the values for x, such that h(x) is strictly less than g(x). We can write this as 9^x + 9 < 103^x and solve for x as follows. 9^x + 9 < 103^x => 3^(2x) - ...

CM
Answered by Carlo M. Maths tutor
3906 Views

Prove the following identity: (1+cos⁡(x)+cos⁡(2x))/(sin⁡(x)+sin⁡(2x) )=cot⁡(x)

Straight away we notice that two trigonometric terms on the left hand side have 2x but there are no 2x on the right hand side therefore we realise that this question will require double angle formulae. If...

JB
Answered by Jessica B. Maths tutor
19563 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning