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A circle with equation x^2+y^2-2x+8y-40=0. Find the circle centre and the radius

2g=-2, -g=1. 2f=-8, -f=4. cc(-2,4). r=√(g^2+f^2-c)=√(4+16+40)=√80=4√5

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Answered by Liam M. Maths tutor
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Integrate ∫x^4+5x^3+sin(2x) dx

∫x^4+5x^3+sin(2x) dx So a basic rule for x functions is that 1. Add 1 to the power 2. divide by the new power. So lets do this for the 2 x terms 1/5x^5+5/4x^4 Now lets look at the sin(2x). A general r...

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Answered by Liam M. Maths tutor
6341 Views

A line joins 2 points (2,9) and (5,4). Calculate the gradient of the straight line and then write down the equation of the straight line.

The first thing to do is to look at the points given and decide if you are going to get a negative or positive gradient. We can determine, from inspection that the gradient will be negative because as the...

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Answered by Liam M. Maths tutor
4929 Views

Find the roots of 2x^2-5x-6=0 to 3dps

if we see the phrase "to N dps" this is a big hint to use the quadratic formula. The first thing we have to do is to is pick out the co-efficients ax^2+bx+c=0 a=2, b=-5, c=-6 Now we can pug thes...

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Answered by Liam M. Maths tutor
4600 Views

Simplify √90+√360+5√10

The object of surds is to look for square numbers in each term and take the square root of them. √90=√9√10=3√10 √360=√36√10=6√10 Therefore adding all the terms together 3√10+6√10+5√10=14√10

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Answered by Liam M. Maths tutor
5008 Views

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