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Find the possible values of x for x^2 = 36-5x.

While this question may appear unfamiliar at first, it is just a quadratic equation in disguise. Rearranging such that it equals 0:

x^2 + 5x - 36 = 0

Now this equation is re...

Answered by Ben H. • Maths tutor

9352 Views

How do I simplify fully (p^3 x p^4)/p^2?

At first this looks quite daunting as it combines a number of different indices (powers) and a fraction.

The rules for indices are just something that you have to learn - so don't worry ...

Answered by Emily R. • Maths tutor

14191 Views

Solve simultaneously: x + y + 3 = 0 and y = 2x^2 +3x - 1

First Step:

I believe here it is important to firstly look at each equation on its own and just try to think how the examiner would want you to answer this type of question.

Answered by Jamie S. • Maths tutor

4741 Views

Solve the equation; 4 cos^2 (x) + 7 sin (x) – 7 = 0, giving all answers between 0° and 360°.

4 cos² (x) + 7sin (x) – 7 = 0 (1)

Using the identity sin² (x) + cos² (x) = 1,

rearrange to give; cos² (x) =...

Answered by Connor S. • Maths tutor

18712 Views

Solve X^2 +13X+48=12

It is first important to get the equation to equal 0, so to do this you minus 12 from each side of the equals symbol, giving youX^2 +13X+36=0Now it is time to think about factorising!The best trick for th...

Answered by Kemba M. • Maths tutor

6034 Views