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If you're asked to solve a quadratic equation, you could factorise it, or you could use the quadratic formula. The quickest way is to factorise, but sometimes the numbers are too tricky to factorise, (...
The first thing we should note here is that we are looking for the area, so we need to recall the formula for the area of a right-angled triangle:
Area = (base x height) / 2KSAnswered by Kirsty S. • Maths tutor12826 Views
Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dxSo we just need to find dy/du and du/dx!In this case u(x)=x-3, so du/dx = 1.from y=u^(-3), dy/du = -3u^(-4).This...
In order to deal with the modulus sign, we must take account of 2 possible cases:
Case 1: |2x + 1| = (2x +1). In this case we can solve algebraicly, preserving the inequality sign, to get...
To solve this problem, we must first differentiate:
Identify that we are able to use the product rule as our expression is of the form y = f(x)g(x) where f(x) = e^(2- x) and g(x) = ln(3x-...
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