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Given that f(x) = x^2 (3x - 1)^(1/2) find f'(x)
This is an example of a question using the product rulelet u = x2 and v = (3x - 1)1/2then u' = 2x and v' = 3 X 1/2 (3x - 1)-1/2 using the product rule we get f'(x) = x
How do I know when to use sine, cos or tan when working with right angled triangles?
When dealing with right angled triangles, you just need to remember 'SOHCAHTOA'. If you struggle to remember this, you may find it easier to recall:'Some Of H
