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2n+1 will always be an odd number (e.g. if n is equal to 3 the answer would be 7, an odd number) So, we square 2n+1 and write this as (2n+1)2 2n +12n 4n...
Un+1=1/Un where U1= 2/3First of all, we need to find U2 and U3 and so on, up until we notice a pattern in the answers. U2 = 1/(2/3) = 3/2U...
Int() in this case will refer to integralsAnswer is: f(x)=(1-x^2)/(1+x^2)=(2-(1+x^2)/(1+x^2)=-1+2/(1+x^2)=> Int(f(x))=Int(-1+2/(1+x^2))=Int(-1)+2Int(1/(1+x^2))=-x+2tan^-1(x)+C
495/3 = 165 => £165 worth of £1 coins124 x 0.5 = 62 => £62 worth of 50p coinsWe know the number of coins that are NOT 20p coins. Therefore, we can subt...
253/2= 25(3x 1/2)(251/2)3= (square root of 25)3(5)3= 125
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