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Differentiating the integral equation with respect to x we obtain: f(ln(x))=nxn-1ln(x)+xn-1=xAnswered by • Maths tutor1567 Views
u=lnx du/dx = 1/x dv/dx=x^-2 v= -1/x =uv - (integral of)vdu/dx (-lnx)/x + integral of x^-2 =(-lnx)/x - 1/x +c
This problem can be solved using Pythagoras Theorem equation: A2 + B2= C2 (see diagram for explanation)Substitute the numbers given in the question into this equatio...
ratios are just fractions not written in fraction form, for example 8:9 ratio just means the first value is 8/(8+9) and the second value is 9/(8+9)if a question says that in a ratio of green apples to red...
This equation can be solved by factorisation. Start off with brackets : (x )(x ) =0. We need two numbers that multiply to give 6 and add/subtract to give 1. Start off with 1 and 6. They multiply to give 6...
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