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Solve for x: logx(25) = log5(x)

logx(25) = log5(x)2logx(5) = log5(x)2/log5(x) = log5(x)2 = (log5(x))^2sqrt(2) = log5(x)x = 5^sqrt(2)

Answered by • Maths tutor

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a) Find the area of a semi circle with diameter 12cm. b) The area of a semi-circle is 60cm^2. Find the radius of the sem-circle.

a) radius = 12/2 = 6cm. Area of a circle = pi x r^2 = 36pi. Area of semi-circle = 36pi / 2 = 18pi cm^2b) Area of full circle = 120. pi x r^2 = 120. r^2 = 120/pi. r = sqr root (120/pi)= 6.18cm

Answered by Ahmed G. • Maths tutor

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Simplify 5p + 2q – 3p – 3q

Firstly, look at the number in front of the letter 'p'. This is 5p and -3p. By ignoring the 'p', as they both have it, do 5-3 which is 2 and so that part of the answer will be 2p. Then look at the letter ...

Answered by Radhika A. • Maths tutor

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Matthew gets £100 for his 16th birthday and chooses to invest the money into a bank with a 2% annual interest rate. By which birthday will Matthew have more than £150 in his account?

This a geometric sequence with first term 'a' as 100 and common ratio 'r' of 1.02. 100 x 1.02ⁿ > 150 1.02ⁿ > 150/100 =1.02ⁿ > 1.5 log₁₀(1.02ⁿ

Answered by • Maths tutor

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What is the length of a if a triangle has lengths of b=6.4cm and c=5.6cm with an angle A=107.9 degrees?

We are going to have to use the cosine rule for this type of question. The cosine rule is a2=b2+c2 - 2bcCosATherefore a2= (6.46.4) + (5.65.6) - (26.45.6)*Cos107.9 If we plug this into ou...

Answered by Maria K. • Maths tutor

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