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This a geometric sequence with first term 'a' as 100 and common ratio 'r' of 1.02. 100 x 1.02n > 150 1.02n > 150/100 =1.02n > 1.5 log10(1.02nAnswered by • Maths tutor3459 Views
We are going to have to use the cosine rule for this type of question. The cosine rule is a2=b2+c2 - 2bcCosATherefore a2= (6.46.4) + (5.65.6) - (26.45.6)*Cos107.9 If we plug this into ou...
Acceleration can be described as the 'rate of change of velocity' as it is simply how quickly the car is increasing/decreasing in velocity. Therefore as the velocity is described...
= (2x^2-3)(2x^2-3) -{(2x^2+2)(2x^2+2)}= 4x^4-6x^2-6x^2+9 -(4x^4+4x^2+4x^2+4)= 4x^4-12x^2+9-4x^4-8x^2-4= -20x^2+5= -5(4x^2-1) or 5(-4x^2+1)
For both the two main subjects I intend on teaching in this platform, I highly recommend to my students to focus on the theory as a first step (this could be a definition, some notes, etc). So, by trying ...
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