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A car is travelling with a velocity of "0.5t^2+t+2" m/s at t=0 (where t is in seconds), find the acceleration of the car at a) t=0 b)t=2

Acceleration can be described as the 'rate of change of velocity' as it is simply how quickly the car is increasing/decreasing in velocity. Therefore as the velocity is described...

DE
Answered by Dominic E. Maths tutor
2779 Views

simply fully (2x^2 -3)^2 - (2x^2 + 2)^2

= (2x^2-3)(2x^2-3) -{(2x^2+2)(2x^2+2)}= 4x^4-6x^2-6x^2+9 -(4x^4+4x^2+4x^2+4)= 4x^4-12x^2+9-4x^4-8x^2-4= -20x^2+5= -5(4x^2-1) or 5(-4x^2+1)

MS
Answered by morgan s. Maths tutor
2544 Views

What is the definition of the slope?

For both the two main subjects I intend on teaching in this platform, I highly recommend to my students to focus on the theory as a first step (this could be a definition, some notes, etc). So, by trying ...

MM
Answered by Maria-Eliza M. Maths tutor
3001 Views

Find d/dx (ln(2x^3+x+8))

Use the chain rule: dy/dx = dy/du * du/dx
Let y = ln(2x^3+x+8)Let u = 2x^3+x+8
dy/dx = d/dx (ln(2x^3+x+8)) = dy/du * du/dx
dy/du = 1/udu/dx = 6x^2 + 1
dy/dx = 1/u * (6x^2 + 1) = (1/(2x...

Answered by Maths tutor
3323 Views

What is the Pythagoras’ theorem and how can it be used to work out the distance between two points?

Pythagoras’ theorem is the formula used to calculate any side of a right-angled triangle. The concept is that the square of the hypotenuse is equal to the sum of the squares on the other two sides. Assign...

SW
Answered by Samuel W. Maths tutor
2059 Views

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