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This equation can be solved by factorisation. Start off with brackets : (x )(x ) =0. We need two numbers that multiply to give 6 and add/subtract to give 1. Start off with 1 and 6. They multiply to give 6...

Draw out a diagram of a right angled triangle. As the lengths of the sides of the triangle are in the ratio 3:4:5, start off by saying each side is 3cm (a), 4cm (b) and 5cm (c) respectively, with 5cm bein...

First we need to factorise the denominator into (x-1)(x+1). Now we identify that 1/(x-1)(x+1) is equivalent to A/(x-1) + B/(x+1) and now we solve to find the values of A and B. By simplifying the equivale...

We can factorise into (x-3)(x-2)=0 to get x=3 and x=2 as solutions for this equation.

The first task is to multiply out the brackets in the numerator. By doing this, we find that the numerator is equivalent to "12 + 2k". We should now simplify the denominator. We can convert it i...