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After t seconds the distance between the bottom of the ladder and the wall is t metres. Let x denote the distance that the top of the ladder has moved after t seconds. Now use the theorem of Pythagoras to...

When we solve this, it's going to be the same process as solving 5(x-6) = 20, except at each step we need to think about whether we change the inequality round or keep it the same. There are two ways of d...

Given y = 2x(x² – 1)⁵, show that
(a) dy/dx = g(x)(x² – 1)⁴ where g(x) is a function to be de...

√40 + √90

= (√10 x √4 ) + (√10 x √9 )

= 2√10 + 3√10=5√10

5(x + 3) < 60Multiple the number outside of the bracket with the contents of the bracket:5x + 15 <60 Next, bring all the numbers to one side 5x <60-15Now simplify 5x < 45Simply further x < ...