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To expand the brackets we consider each bracket separately, (2m-3) which is multiplied by (m+1). Consider first the first identity in each bracket:2m x m = 2m²Then consider the first identity a...

Solution: 12x² + 3

Working:

General differentiation formular:  d/dx (axⁿ ) = an(x^n-1) 

So we multiply the coefficient (constant infront) of the x term...

To do this, we will only consider the direction vectors of each line. That is to say, the vector 'attached' to our λ and μ terms (which are called scalar parameters).We will do this because the angle betw...

Use the number of marks as a guide - if the paper is worth 80 marks and you're given 1.5 hours, I'd allocate 1 minute per mark which would give you 10 minutes (or more if you're quick) to check over your ...

As we appreciate the rule 1: gradient of line PQ multiplied by the gradient of the line perpendicular to it equals -1. Formula: m x mn=-1We use this to find the gradient of line PQ:Firstly, we find the gr...