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How do I find the area bounded by the curve y=-x^2+4 and the line y=-x+2?

First sketch the line and the curve on the same axes (I would show this using the whiteboard).Then we want to find the points of intersection so set the two equations equal to each other and rearrange to ...

Answered by Sarah H. • Maths tutor

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Simplify (3x^2-8x-3)/(2x^2-6x)

(3x + 1)/(2x)I would use the whiteboard to explain the process

Answered by Romeo E. • Maths tutor

3021 Views

Find the roots of the equation (x^2+5x+4)/(x^2-3x+2)

Finding the root means finding the solution when the equation is equal to zero, so when (x^2+5x+4)/(x^2-3x+2)=0. This happens when the numerator x^2+5x+4 is equal to zero so we have to find the roots. To ...

Answered by Charlotte S. • Maths tutor

3078 Views

A piece of wire is 240cm long. Peter cuts two 45 cm lengths off the wire. He then cuts the rest of the wire into as many 40cm length as possible. How many wires of 40cm can be cut?

Two 45cm lengths cut off 240cm long wire. 240 - (2*45) = 150cmHow many 40cm length wires can be cut out of the remainder 150cm wire?150/40= 3.75As we are looking for entire 40cm length wires, we disregard...

Answered by Federico B. • Maths tutor

8046 Views

Find the area under the curve y=xsin(x), between the limits x=-pi/2 and x=pi/2.

We are going to need to use integration for this problem as it involves finding an area under a curve. Also notice that y is a product of two functions of x ; x and sin(x). This means in this particular c...

Answered by Oakley Y. • Maths tutor

3155 Views