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Stationary points occurs when the gradient of the graph is equal to 0, i.e. dy/dx = 0. Differentiate y with respect to x to get dy/dx = 4x + 4.So making 4x + 4 = 0 gives x = -1. Substituting this into the...
When you differentiate the function that gives the gradient. Therefore differentiate to get dy/dx= 15x^2 + 3. Make this equal to 0 to get 15x^2 + 3=0 and rearrange to get the value of x as required so 15x...
Answer: a(5-3a)Explanation: We take the highest common factor of both of the terms, which is a and we put it outside of the bracket. Then, in the bracket we put two terms that when multiplied by a, the pr...
Our A-level knowledge does not give us any identities to be able to integrate this from memory. But what we do have from memory is that the derivative of ln(x) is 1/x. Why would this help us? Let's take a...
j = 2, k = 7
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