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Solve the simultaneous equations for x and y: 3x+2y = 14 and 5x-y = 6

3x + 2y = 14 -> 15x - y = 6 -> 2Answer: x = 2 and y =4Solution:multiply both sides of equation 2 by 2: 10x - 2y = 12add this to equation 1: 3x + 10x + 2y -2y = 14 +12simplify: 13x = 26divide by 13: ...

MF
Answered by Megan F. Maths tutor
4617 Views

x - 2y = 1 , x^2 + y^2 = 13 find the solutions to this quadratic equation

equation 1) x - 2y = 1equation 2) x2 + y2 = 13
Rearrange equation 1 to: x = 1+2ysubstitute into equation 2: (1+2y)2 + y2=13expand first bracket: (1+2y)(1+2...

CS
Answered by Caitlin S. Maths tutor
2760 Views

solve y=3x+4, x=y+1

Equation 1) y=3x+4Equation 2) y=x+1
Rearrange equation 2 into terms of x as this is the simplest: x= y-1 (We do this by subtracting 1 off of each side to get X by itself)Substitute new equation 2 int...

CS
Answered by Caitlin S. Maths tutor
2831 Views

Factorise x 2 − x − 12

X2 - X -12 look at what numbers will add together and make 12. (2x6) or (3x4)Then see what of these combinations, when added together, makes -1. you have to consider that one of these values wi...

VV
Answered by Vicky V. Maths tutor
4094 Views

How can you integrate the function (5x - 1)/(x^(3)-x)?

The first thing to do, is see if it can be simplified: 5x -1 can't, however x^(3) - x simplifies to x(x^2 - 1) and then to x(x-1)(x+1) by the difference of two squares. So now we have (5x - 1)/(x(x-1)(x+1...

AW
Answered by Adam W. Maths tutor
2901 Views

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